Saben Lee Net Worth 2024 – Famous American basketball player “Saben Lee” has a net worth of $1 million to $4 million and was born on June 23, 1999.
Saben Lee Net Worth
According to online sources, the net worth of Saben Lee (American basketball player) is estimated at $1 million to $4 million. Saben Lee’s net worth is largely a result of his success as an American basketball guard.
| Name | Saben Lee |
| Estimated Net Worth | $1 million – $4 million |
| Profession | American basketball player |
| Date of birth | June 23, 1999 |
| Age | 24 years old |
| Height | 188 cm |
| Weight | 83 kg (182 lbs) |
| Birthplace | St. Louis, Missouri, United States |
| Nationality | American |
Who is Saben Lee?
Saben Lee, born 1999, is an American professional basketball player who is currently under a two-way contract with the Phoenix Suns. His journey from high school star in Arizona to navigating the competitive landscape of the NBA is a story of perseverance, athleticism and the pursuit of a dream.
Growing up in Phoenix, basketball was ingrained in Lee’s life. He honed his skills at Corona del Sol High School, making the All-State First Team and leading his team to the state championship game. His talent caught the attention of Vanderbilt University, where he continued to excel.
Lee’s college career was marked by consistent scoring and playmaking. He averaged more than 18 points per game in his junior and senior seasons, earning him All-SEC Second Team honors. His leadership and athleticism were instrumental in Vanderbilt’s success, making him a projected first-round pick in the 2020 NBA Draft.
| Real name | Saben Anthony Lee |
| Nickname | Saben Lee |
| Date of birth | June 23, 1999 |
| Age | 24 years old |
| Height | 188 cm |
| Weight | 83 kg (182 lbs) |
| Birthplace | St. Louis, Missouri, United States |
| Sex | Male |
| Profession | American basketball player |
| Nationality | American |
| Education | Vanderbilt University (2017-2020), Corona Del Sol High School |
| Sign of the zodiac | Cancer |
| Parent | Amp Lee |
Saben Lee Early Life
Born on June 23, 1999 in St. Louis, Missouri, Saben Lee is 6 feet 2 inches (1.88 meters) tall and weighs 183 pounds (83 kilograms). His basketball journey began during his time at Corona del Sol in Tempe, Arizona, where he initially played on the freshman team and later served as a reserve on the varsity team during his sophomore year.
After transferring to college basketball, Lee played for the Vanderbilt Commodores from 2017 to 2020. After that, in the 2020 NBA Draft, he was selected by the Utah Jazz as the 38th pick in the 2nd round. He officially entered the NBA and made his debut on January 6, 2021. Currently, Lee is a valued player of the Phoenix Suns.
Saben Lee Height and Weight
Saben Lee, a talented basketball player, boasts a height of 188 centimeters and maintains a weight of 83 kilograms (182 pounds). These physical attributes play a significant role in defining Lee’s performance on the basketball court.
At 188 centimeters tall, Lee possesses a powerful frame that allows him to excel in various aspects of the game. His height allows him to navigate the court efficiently, make precise passes and move toward the basket with agility and speed. Additionally, his height gives him an advantage in defensive situations, allowing him to contest shots and disrupt opposing players.
Physical characteristics | Measurements |
Height | 188 cm |
Weight | 83 kg (182 lbs) |
Stay well-informed with current updates on the net worth of your favorite celebrities and indulge in interesting content and anecdotes. Stay up to date with the latest updates and dive into the big news, all available on Fresherslive!
Disclaimer: The above information is for general information purposes only. All information on the website is provided in good faith, however we make no representations or warranties of any kind, express or implied, as to the accuracy, adequacy, validity, reliability, availability or completeness of any information on the website.
Categories: Net Worth
Source: HIS Education